2q^2-q-210=0

Solution for 2q^2-q-210=0 equation:

2q^2-q-210=0

We add all the numbers together, and all the variables

2q^2-1q-210=0

a = 2; b = -1; c = -210;
Δ = b2-4ac
Δ = -12-4·2·(-210)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-41}{2*2}=\frac{-40}{4}
=-10
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+41}{2*2}=\frac{42}{4}
=10+1/2
$